0=-8+8x^2

Solution for 0=-8+8x^2 equation:

0=-8+8x^2

We move all terms to the left:

0-(-8+8x^2)=0

We add all the numbers together, and all the variables

-(-8+8x^2)=0

We get rid of parentheses

-8x^2+8=0

a = -8; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·(-8)·8
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*-8}=\frac{-16}{-16}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*-8}=\frac{16}{-16}
=-1
$